For a circuit using DC current, if the resistance doubles, what will happen to the amperage?

In a circuit powered by direct current (DC), Ohm's Law applies, which states that the relationship between voltage (V), current (I), and resistance (R) can be defined by the formula: V = I × R. When the resistance in the circuit doubles, while the voltage remains constant, the current (or amperage) will indeed be affected.

To understand this, consider Ohm's Law rearranged to calculate current: I = V/R. If the resistance (R) increases while the voltage (V) stays the same, the value of I must decrease. Specifically, if the resistance is doubled, the new amperage can be expressed as I' = V/(2R). This clearly illustrates that the amperage will be half of what it was previously.

Thus, when resistance doubles, the current decreases to half its original value, leading to a decrease in amperage. This is consistent with the fundamental principles of electrical circuits and the behavior of current under changing resistance conditions.